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x^2+0.6x-1.6=0
a = 1; b = 0.6; c = -1.6;
Δ = b2-4ac
Δ = 0.62-4·1·(-1.6)
Δ = 6.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.6)-\sqrt{6.76}}{2*1}=\frac{-0.6-\sqrt{6.76}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.6)+\sqrt{6.76}}{2*1}=\frac{-0.6+\sqrt{6.76}}{2} $
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